Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.4 De Moivre's Theorem: Powers and Roots of Complex Numbers - 8.4 Exercises - Page 377: 46

Answer

$(cos~\theta+i~sin~\theta)^2 = cos^2~\theta - sin^2~\theta + 2i~cos~\theta ~sin~\theta$

Work Step by Step

$(cos~\theta+i~sin~\theta)^2 = cos^2~\theta + 2i~cos~\theta ~sin~\theta - sin^2~\theta$ $(cos~\theta+i~sin~\theta)^2 = cos^2~\theta - sin^2~\theta + 2i~cos~\theta ~sin~\theta$
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