Answer
$(cos~\theta+i~sin~\theta)^2 = cos^2~\theta - sin^2~\theta + 2i~cos~\theta ~sin~\theta$
Work Step by Step
$(cos~\theta+i~sin~\theta)^2 = cos^2~\theta + 2i~cos~\theta ~sin~\theta - sin^2~\theta$
$(cos~\theta+i~sin~\theta)^2 = cos^2~\theta - sin^2~\theta + 2i~cos~\theta ~sin~\theta$