Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.3 The Product and Quotient Theorems - 8.3 Exercises: 31

Answer

$[2cis(\frac{5\pi}{9})]^2$ = $-3.7588 - 1.3681i$ (Using calculator and corr. to 4 decimal places)

Work Step by Step

$[2cis(\frac{5\pi}{9})]^2$ = $2^2 cis(\frac{5\pi}{9}) cis(\frac{5\pi}{9})$ = $4 cis(\frac{5\pi}{9} + \frac{5\pi}{9})$ (Product Theorem) = $4 cis(\frac{10\pi}{9})$ = $-3.7588 - 1.3681i$ (Using calculator and corr. to 4 decimal places)
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