Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.1 Complex Numbers - 8.1 Exercises - Page 359: 115

Answer

Total Impedance of the circuit = 110 + 32$i$ ohms $(\Omega)$

Work Step by Step

Total Impedance of the circuit = Sum of Individual Impedance = Sum of Individual Resistance + Sum of Individual Reactance = 50 + 60 + 15$i$ + 17$i$ ohms $(\Omega)$ = 110 + 32$i$ ohms $(\Omega)$
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