## Trigonometry (10th Edition)

The statement "A number can be both real and complex" is true. It is because, for any complex number $z$ = $a + bi$, when the imaginary part $b = 0$, $z$ will be equal to $a$, which is real and complex (since real is a subset of complex). And, in case of both $a$ and $b$ equal to $0$, $z$ will be equal to $0$, which is both real and complex as well. The only exception is when $a$ = $0$, $z$ will be equal to $bi$, which is not real but just pure imaginary. With this exception, it cannot be real but just complex only.