Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 7 - Applications of Trigonometry and Vectors - Section 7.5 Applications of Vectors - 7.5 Exercises - Page 338: 31a

Answer

$\vert ~R ~\vert = \sqrt{5}$ $\sqrt{5}$ inches of rain falls

Work Step by Step

$R = i-2j$ We can find the magnitude of R: $\vert ~R ~\vert = \sqrt{(1)^2+(-2)^2}$ $\vert ~R ~\vert = \sqrt{5}$ $\sqrt{5}$ inches of rain falls
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