Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 7 - Applications of Trigonometry and Vectors - Section 7.3 The Law of Cosines - 7.3 Exercises - Page 318: 75b

Answer

$C = 92.2^{\circ}$

Work Step by Step

We can try to use the law of cosines to find $C$: $c^2 = a^2+b^2-2ab~cos~C$ $2ab~cos~C = a^2+b^2-c^2$ $cos~C = \frac{a^2+b^2-c^2}{2ab}$ $cos~C = \frac{13^2+7^2-15^2}{(2)(13)(7)}$ $cos~C = -0.03846$ $C = arccos(-0.03846)$ $C = 92.2^{\circ}$
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