Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 7 - Applications of Trigonometry and Vectors - Section 7.1 Oblique Triangles and the Law of Sines - 7.1 Exercises - Page 299: 56b

Answer

The distance between the house and the fire is $~~7079.7~ft$

Work Step by Step

The ground coordinates of the house are $~~(x_h, y_h) = (1131.8, 4390.2)$ The ground coordinates of the fire are $~~(x_f,y_f)= (2277.5, -2596.2)$ We can find the distance between the house and the fire: $d = \sqrt{(x_h-x_f)^2+(y_h-y_f)^2}$ $d = \sqrt{(1131.8-2277.5)^2+[4390.2-(-2596.2)]^2}$ $d = \sqrt{50122413.45}$ $d = 7079.7~ft$ The distance between the house and the fire is $~~7079.7~ft$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.