Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 5 - Trigonometric Identities - Section 5.4 Sum and Difference Identities for Sine and Tangent - 5.4 Exercises - Page 223: 77a

Answer

$F = 425$

Work Step by Step

$F = \frac{0.6W~sin(\theta+90^{\circ})}{sin~12^{\circ}}$ Let $W = 170~lb$ and let $\theta = 30^{\circ}$ $F = \frac{(0.6)(170)~sin(30^{\circ}+90^{\circ})}{sin~12^{\circ}}$ $F = \frac{102~sin(120^{\circ})}{sin~12^{\circ}}$ $F = 425$
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