Answer
$sec^2~B = \frac{1}{cos^2~B} = \frac{1}{1-sin^2~B}$
Work Step by Step
We can verify the identity:
$sec^2~B = \frac{1}{cos^2~B} = \frac{1}{1-sin^2~B}$
Trigonometry (10th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
0321671775
ISBN 13:
978-0-32167-177-6
Chapter 5 - Test - Page 244: 10
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