Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 4 - Graphs of the Circular Functions - Section 4.5 Harmonic Motion - 4.5 Exercises - Page 179: 4a

Answer

$s(t)=-4\cos\frac{5\pi}{3}t$

Work Step by Step

The equation of the function is $s(t)=a \cos wt$. We know that $s(0)=-4$. A negative sign means that the object is pulled down at the start. Since the function is cosine, this means that $a=-4$. We also know that the period is 1.2 seconds. We can find the value of $w$ using the period through the formula: Period$=\frac{2\pi}{w}$ $1.2=\frac{2\pi}{w}$ $w=\frac{2\pi}{1.2}$ $w=\frac{5\pi}{3}$ Substituting the values of $a$ and $w$, we find that the equation is: $s(t)=-4\cos\frac{5\pi}{3}t$
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