Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 4 - Graphs of the Circular Functions - Section 4.5 Harmonic Motion - 4.5 Exercises - Page 179: 3a

Answer

$s(t)=-3\cos 2.5\pi t$

Work Step by Step

The equation of the function is $s(t)=a \cos wt$. We know that $s(0)=-3$. A negative sign means that the object is pulled down at the start. Since the function is cosine, this means that $a=-3$. We also know that the period is 0.8 seconds. We can find the value of $w$ using the period through the formula: Period$=\frac{2\pi}{w}$ $0.8=\frac{2\pi}{w}$ $w=\frac{2\pi}{0.8}$ $w=2.5\pi$ Substituting the values of $a$ and $w$, we find that the equation is: $s(t)=-3\cos 2.5\pi t$
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