#### Answer

$B$

#### Work Step by Step

The cosecant function is undefined when $x=..., -3\pi, -2\pi, -\pi, 0,\pi,2\pi, 3\pi...$
Thus, its graph has the vertical asymptotes $x=..., -3\pi, -2\pi, -\pi, 0, \pi, 2\pi, 3\pi, ...$
This means that the possible graphs of $y=−\csc{x}$ are the ones in Options B and D.
Note that when $x=\frac{\pi}{2}$ , the value of $y=−\csc{x}$ is $-1$.
Only the graph in Option B satisfies this.
Thus, the graph of $y=−\csc{x}$ must be the one in Option B.