Answer
$y = -2+\frac{2}{3}~tan~(\frac{3}{4}x-\pi)$
We can see the graph below.
Work Step by Step
$y = -2+\frac{2}{3}~tan~(\frac{3}{4}x-\pi)$
When $x = -\frac{2\pi}{3}$, then $y = -2+\frac{2}{3}~tan~(-\frac{3\pi}{2})~~$ (which is undefined)
When $x = -\frac{\pi}{3}$, then $y = -2+\frac{2}{3}~tan~(-\frac{5\pi}{4}) = -\frac{8}{3}$
When $x = 0$, then $y = -2+\frac{2}{3}~tan~(-\pi) = -2$
When $x = \frac{\pi}{3}$, then $y = -2+\frac{2}{3}~tan~(-\frac{3\pi}{4}) = -\frac{4}{3}$
When $x = \frac{2\pi}{3}$, then $y = -2+\frac{2}{3}~tan~(-\frac{\pi}{2})~~$ (which is undefined)
We can see the graph below.