#### Answer

Refer to the graph below.

#### Work Step by Step

RECALL:
The graph of $y=a \cdot \sin{[b(x−d)]}$ has:
amplitude = $|a|$
period = $\frac{2\pi}{b}$
phase shift = $|d|$, to the left when $d\lt0$, to the right when $d\gt0$
Write the given function in the form $y=a \cdot \sin{[b(x−d)]}$ by factoring out $\frac{3}{4}$ inside the sine function to obtain:
$y=−\frac{1}{4}\sin{[\frac{3}{4}(x+\frac{\pi}{6})]}$
The given function has:
$a=-\frac{1}{4}$
$b=\frac{3}{4}$
$d=-\frac{\pi}{6}$
Thus, the given function has:
amplitude = $|−\frac{1}{4}|=\frac{1}{4}$
period = $\frac{2\pi}{\frac{3}{4}}=\frac{8\pi}{3}$
phase shift = $|-\frac{\pi}{6}|=\frac{\pi}{6 }$ to the left
Therefore, the graph of the given function has the following properties/characteristics:
amplitude = $\frac{1}{4}$, which means the y-values range from $−\frac{1}{4}$ to $\frac{1}{4}$
phase shift = $\frac{\pi}{6}$ units to the left
one period interval = $[-\frac{π}{6},\frac{5\pi}{2}]$
Refer to the graph in the answer part above.