Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 4 - Graphs of the Circular Functions - Section 4.1 Graphs of the Sine and Cosine Functions - 4.1 Exercises - Page 148: 65

Answer

When $T = 2$, the point on the unit circle lies in the second quadrant. The x coordinate is $-0.416$ and the y coordinate is $0.909$ The point on the unit circle is $~~(-0.416, 0.909)$

Work Step by Step

$x = cos~T$ $y = sin~T$ When $T = 2$: $x = cos~T$ $x = cos~2$ $x = -0.416$ $y = sin~T$ $y = sin~2$ $y = 0.909$ When $T = 2$, the point on the unit circle lies in the second quadrant. The x coordinate is $-0.416$ and the y coordinate is $0.909$ The point on the unit circle is $~~(-0.416, 0.909)$
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