Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 4 - Graphs of the Circular Functions - Section 4.1 Graphs of the Sine and Cosine Functions - 4.1 Exercises - Page 146: 56a

Answer

Amplitude$=3.8$ Period$=\frac{1}{20}$

Work Step by Step

For the graph of $y=a\cos x$, the amplitude is $|a|$. Therefore, for the case of $E=3.8\cos 40\pi t$, the amplitude is $|3.8|=3.8$. In addition, the period of the graph $y=\cos bx$ is $\frac{2\pi}{b}$. Therefore, for the case of $E=3.8\cos 40\pi t$, the period is $\frac{2\pi}{40\pi}=\frac{2}{40}=\frac{1}{20}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.