Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 4 - Graphs of the Circular Functions - Section 4.1 Graphs of the Sine and Cosine Functions - 4.1 Exercises - Page 145: 47b

Answer

15

Work Step by Step

The amplitude of a periodic function is half the difference between the maximum and minimum values. Since the maximum value is 80 while the minimum value is 50, Amplitude$=\frac{1}{2}(80-50)$ Amplitude$=\frac{1}{2}(30)$ Amplitude$=15$
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