#### Answer

B

#### Work Step by Step

Using the formula $\frac{2\pi}{b}$, we find that the period of $y=\sin 2x$ is:
$\frac{2\pi}{b}=\frac{2\pi}{2}=\pi$
In addition, the formula $y=\sin 2x$ stipulates that the amplitude of the function is 1.
Therefore, we need to find a sin wave whose amplitude is 1 and whose period is $\pi$. We find that graph of option B is the correct answer in this regard.