#### Answer

$\sqrt3$

#### Work Step by Step

RECALL:
$\tan{x} = \dfrac{\sin{x}}{\cos{x}}$
The angle $\frac{\pi}{3}$ is a special angle and the following values are known:
$\sin{\frac{\pi}{3}}=\frac{\sqrt3}{2}$
$\cos{\frac{\pi}{3}}=\frac{1}{2}$
Thus,
$\tan{\frac{\pi}{3}} = \dfrac{\sin{\frac{\pi}{3}}}{\cos{\frac{\pi}{3}}}=\dfrac{\frac{\sqrt3}{2}}{\frac{1}{2}}=\frac{\sqrt3}{2} \cdot \frac{2}{1}=\sqrt3$