Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 3 - Radian Measure and the Unit Circle - Section 3.2 Applications of Radian Measure - 3.2 Exercises - Page 109: 80

Answer

$d=(\frac{L}{\theta})(1-\cos \frac{\theta}{2})$

Work Step by Step

Substituting the answer from 77, $r=\frac{L}{\theta}$, into the answer of 79: $d=r(1-\cos \frac{\theta}{2})$ $d=(\frac{L}{\theta})(1-\cos \frac{\theta}{2})$ This is the formula that gives $d$ for specific values of $\theta$.
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