Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 3 - Radian Measure and the Unit Circle - Section 3.2 Applications of Radian Measure - 3.2 Exercises - Page 106: 47

Answer

$60^{\circ}$

Work Step by Step

Step 1: The formula to be used here is $A=\frac{1}{2}r^{2}\theta$ where $A$ is the area of the sector of the circle of radius $r$ and central angle $\theta$. Step 2: Substituting the values in the question, $6\pi=\frac{1}{2}(6^{2})\theta$ Step 3: Multiplying both sides by 2, $6\pi\times2=\frac{1}{2}\times(6^{2})\times\theta\times2$ Step 4: $12\pi=36\theta$ Step 5: Multiplying both sides by $\frac{1}{36}$, $12\pi\times\frac{1}{36}=36\theta\times\frac{1}{36}$ Step 6: $\theta=\frac{\pi}{3}$ Step 7: Converting radians to degrees, $\frac{\pi}{3}=\frac{\pi}{3}(\frac{180^{\circ}}{\pi})=60^{\circ}$ Step 8: Therefore, the required angle is $60^{\circ}$.
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