Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 3 - Radian Measure and the Unit Circle - Section 3.1 Radian Measure - 3.1 Exercises - Page 99: 71

Answer

$\dfrac{2\sqrt3}{3}$

Work Step by Step

Convert the angle measure to degrees to obtain: $=\frac{\pi}{6} \cdot \frac{180^o}{\pi} = 30^o$ Thus, $\sec{(\frac{\pi}{6})} \\= \sec{30^o}$ From Section 2.1 (page 50) , we learned that: $\sec{30^o} = \dfrac{2\sqrt3}{3}$
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