Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Quiz (Sections 2.1-2.3) - Page 67: 3

Answer

w = 18 x = 31.18 y = 18 z = 25.46

Work Step by Step

To complete this question, we are looking to find variables: x, y, z, & w. We should start by examining what we know from the geometry. We know that there are two right angle triangles, meaning that at least one of the angles is 90$^{\circ}$. With this information, we can separate the two triangles and then we have a 30-60-90 triangle and a 45-45-90 triangle, since all the angles in a triangle must add to 180$^{\circ}$. Now, lets find w. SOH = $\sin$ $\theta$ = $\frac{Opposite}{Hypotenuse}$ $\theta$ = 30$^{\circ}$ , Opposite = w , Hypotenuse = 36 $\sin$ 30$^{\circ}$ = $\frac{w}{36}$ 36$\times\sin$ 30$^{\circ}$ = w w = 18 We can do the same to find x. CAH = $\cos$ $\theta$ = $\frac{Adjacent}{Hypotenuse}$ $\theta$ = 30$^{\circ}$ , Adjacent = x , Hypotenuse = 36 $\cos$ 30$^{\circ}$ = $\frac{x}{36}$ 36$\times\cos$ 30$^{\circ}$ = x x = 31.18 We can now use w to find y & z. TOA = $\tan\theta$ = $\frac{Opposite}{Adjacent}$ $\theta$ = 45$^{\circ}$ , w = 18 $\tan\theta$ = $\frac{w}{y}$ $\tan45^{\circ}$ = $\frac{18}{y}$ y = $\frac{18}{\tan45^{\circ}}$ y = 18 And, lastly. $\sin$ $\theta$ = $\frac{w}{z}$ $\sin$ $45$$^{\circ}$ = $\frac{18}{z}$ z = $\frac{18}{\sin 45^{\circ}}$ z = 25.46
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