Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.5 Further Applications of Right Triangles - 2.5 Exercises - Page 83: 28

Answer

$y = (tan\theta) x - a \tan\theta $ $m = \tan\theta$ and $c=-a\tan\theta$

Work Step by Step

Slope - intercept form of a straight line can be given by equation $y=mx+c$. $y =(x-a) \times tan\theta = (tan\theta) x - a \tan\theta$ By putting point (x, y) (a, 0), we will see that LHS=RH, hence function y passes through (a, 0).
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