## Trigonometry (10th Edition)

The sun's diameter is approximately $864,900~miles$
We can convert the angle to radians: $\theta = 32' = (\frac{32}{60})^{\circ}(\frac{\pi~rad}{180^{\circ}}) = 0.0093084~rad$ The arc length is equal to $\theta~d$. Since $\theta$ is a small angle, the diameter of the sun is almost equal to the arc length. Therefore, we can use the arc length to approximate the sun's diameter. We can find the arc length $S$ to approximate the sun's diameter: $S = \theta~d$ $S = (0.0093084~rad)(92,919,800~mi)$ $S = 864,900~mi$ The sun's diameter is approximately $864,900~miles$