#### Answer

False

#### Work Step by Step

$\tan ^{2} (72^{\circ} 25') + 1 = \sec ^{2} (72^{\circ}25')$
$9.957710155 + 1 \ne 0.091259944264$

Published by
Pearson

ISBN 10:
0321671775

ISBN 13:
978-0-32167-177-6

False

$\tan ^{2} (72^{\circ} 25') + 1 = \sec ^{2} (72^{\circ}25')$
$9.957710155 + 1 \ne 0.091259944264$

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