Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.2 Trigonometric Functions of Non-Acute Angles - 2.2 Exercises - Page 61: 79

Answer

$30^{\circ}$ and $150^{\circ}$

Work Step by Step

1. Since $sin$ $\theta$ is positive, $\theta$ must be in quadrant I or II. 2.. The reference angle is $30^{\circ}$, so the other angle must be $180^{\circ} - 30^{\circ} = 150^{\circ}$.
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