Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.2 Trigonometric Functions of Non-Acute Angles - 2.2 Exercises - Page 60: 78b

Answer

$L\approx 369ft$

Work Step by Step

1. Use the formula $L=\frac{(\theta_2 - \theta_1)S^{2}}{200(h+s \times tan A)}$ 2. Substitute $h=1.9ft$, $A = 1.5^{\circ}$, $\theta_1=-3^{\circ}$, $\theta_2 = 4^{\circ}$ and $S=339ft$ $L=\frac{(4+3)\times 336^{2}}{200(1.9 +336 \times tan 1.5^{\circ})}=369ft$
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