Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 2 - Acute Angles and Right Triangles - Section 2.1 Trigonometric Functions of Acute Angles - 2.1 Exercises: 60

Answer

$sin (45^{\circ}) = \frac{1}{\sqrt{2}}$

Work Step by Step

Let's consider a triangle with angles $45^{\circ}, 45^{\circ},$ and $90^{\circ}$ that has sides of length $1, 1,$ and $\sqrt{2}$. Let $x = 1, y= 1$, and $r = \sqrt{2}$. Then: $sin(45^{\circ}) = \frac{y}{r} = \frac{1}{\sqrt{2}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.