## Trigonometry (10th Edition)

$\tan\theta=-0.56616682$
1. We will use the identity $\sin^{2}\theta+\cos^{2}\theta=1$. 2. Substitute the value of sine theta into expression: $(0.49268329)^{2}+cos^{2}\theta=1$ $\cos^{2}\theta=0.75726318$ $\cos\theta=-0.870208$ (we need to remember that cosine is negative in QII) 3. Insert values to find the tangent $\tan\theta=\frac{0.49268629}{-0.87020870}=-0.56616682$