Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 1 - Trigonometric Functions - Section 1.3 Trigonometric Functions - 1.3 Exercises: 77

Answer

$tan(-900^{\circ}) = 0$

Work Step by Step

Since each full rotation is $360^{\circ}$, the angle $-900^{\circ}$ is in the same position as $-900^{\circ}+n\times 360^{\circ}$ for any integer $n$. When $n = 3$: $\theta = -900^{\circ}+n\times 360^{\circ}$ $\theta = -900^{\circ}+(3)(360^{\circ})$ $\theta = 180^{\circ}$ For this angle, we can use the point (-1, 0). x = -1 y = 0 r = 1 We can find the value of $tan(-900^{\circ})$: $tan(-900^{\circ}) = \frac{y}{x}$ $tan(-900^{\circ}) = \frac{0}{-1} = 0$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.