Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 1 - Trigonometric Functions - Section 1.1 Angles - 1.1 Exercises - Page 9: 129

Answer

$4$.

Work Step by Step

Using the Pythagorean theorem: $r=\sqrt{ a^2+b^2}$, here: $r=\sqrt{0^2+(-4)^2}=\sqrt {0+16}=\sqrt {16}=4$.
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