Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 1 - Trigonometric Functions - Section 1.1 Angles - 1.1 Exercises - Page 9: 125

Answer

$2$.

Work Step by Step

Using the Pythagorean theorem: $r=\sqrt{ a^{2}+b^{2}}$, here: $r=\sqrt{ ({-1})^{2}+{(\sqrt{3}})^{2}}=\sqrt{1+3}=\sqrt{4}=2$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.