Answer
For $y = x^3 - x$, it has a graph that is symmetric with respect to the origin.
Work Step by Step
In $y = x^3 - x$,
a) To test for symmetry w.r.t the $x$-axis
replace $y$ with $-y$, we have
$(-y) = x^3 - x$
$-y = x^3 - x$
$y = -x^3 + x$
which the result is not the same as the original equation, therefore, it is not symmetric with respect to the $x$-axis
b) To test for symmetry w.r.t the $y$-axis
replace $x$ with $-x$, we have
$y = (-x)^3 - (-x)$
$y = -x^3 + x$
which the result is not the same as the original equation, therefore, it is not symmetric with respect to the $y$-axis
c) To test for symmetry w.r.t the origin
replace $x$ with $-x$ and $y$ with $-y$, we have
$(-y) = (-x)^3 - (-x)$
$-y = -x^3 + x$
$y = x^3 - x$
which the result is the same as the original equation, therefore, it is symmetric with respect to the origin