Answer
$(-1, \sqrt{3})$ is equivalent to $(2, 120^\circ)$ in polar coordinates.
Work Step by Step
For $(-1, \sqrt{3})$,
$r = \sqrt{(-1)^2 + (\sqrt{3})^2} = 2$
$tan\theta = \frac{\sqrt{3}}{-1} = -\sqrt{3}$
$\theta = arctan (-\sqrt{3}) = 120^\circ$ (As $(-1, \sqrt{3})$ is in the second quadrant)
Hence, $(-1, \sqrt{3})$ is equivalent to $(2, 120^\circ)$ in polar coordinates.
