#### Answer

$2$

#### Work Step by Step

$2$ cis $0^{\circ}$=$2(\cos0^{\circ}+i\sin0^{\circ})$
It is known that $\cos0^{\circ}=1$ and $\sin0^{\circ}=0$
Substituting these values in the expression and solving:
$2(\cos0^{\circ}+i\sin0^{\circ})=2(1+i(0))=2(1)=2$