Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.6 Parametric Equations, Graphs, and Applications - 8.6 Exercises - Page 406: 56

Answer

$x = cos~t$ $y = sin~t$ These parametric equations trace out the unit circle in the counterclockwise direction. $x = cos~t$ $y = -sin~t$ These parametric equations trace out the unit circle in the clockwise direction.

Work Step by Step

$x = cos~t$ $y = sin~t$ When t = 0: $x = cos~0 = 1$ $y = sin~0 = 0$ As t increases from $t = 0$ to $t = \frac{\pi}{2}$: $x$ decreases from $x = 1$ to $x=0$ $y$ increases from $y = 0$ to $y=1$ Thus, starting from the point $(1,0)$, the points $(x,y)$ trace out the unit circle in the first quadrant as t increases from $t=0$ to $t = \frac{\pi}{2}$. This means that the unit circle is being traced in the counterclockwise direction. $x = cos~t$ $y = -sin~t$ When t = 0: $x = cos~0 = 1$ $y = -sin~0 = 0$ As t increases from $t = 0$ to $t = \frac{\pi}{2}$: $x$ decreases from $x = 1$ to $x=0$ $y$ decreases from $y = 0$ to $y=-1$ Thus, starting from the point $(1,0)$, the points $(x,y)$ trace out the unit circle in the fourth quadrant as t increases from $t=0$ to $t = \frac{\pi}{2}$. This means that the unit circle is being traced in the clockwise direction.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.