## Trigonometry (11th Edition) Clone

(a) We can see the graph below. (b) $y = x-6$, where $x \geq 2$
$x = t^2+2$ $y = t^2-4$ (a) t = -2: $x = (-2)^2+2 = 6$ $y = (-2)^2-4 = 0$ t = -1: $x = (-1)^2+2 = 3$ $y = (-1)^2-4 = -3$ t = 0: $x = (0)^2+2 = 2$ $y = (0)^2-4 = -4$ t = 1: $x = (1)^2+2 = 3$ $y = (1)^2-4 = -3$ t = 2: $x = (2)^2+2 = 6$ $y = (2)^2-4 = 0$ (Note that $x \geq 2$) We can see the graph below. (b) $x = t^2+2$ $t = \sqrt{x-2}$ $y = t^2-4$ $y = (\sqrt{x-2})^2-4$ $y = (x-2) - 4$ $y = x-6$ (Note that $x \geq 2$)