Answer
$(x,y) = (\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2})$, which matches up with option (D)
Work Step by Step
$x = cos~t$
$y = sin~t$
When $t = \frac{\pi}{4}$:
$x = cos~(\frac{\pi}{4}) = \frac{\sqrt{2}}{2}$
$y = sin~(\frac{\pi}{4}) = \frac{\sqrt{2}}{2}$
Then $(x,y) = (\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2})$, which matches up with option (D)