Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.2 Trigonometric (Polar) Form of Complex Numbers - 8.2 Exercises - Page 371: 38


$-3\sqrt 2+3i\sqrt 2$

Work Step by Step

$6$ cis $135^{\circ}$=$6(\cos135^{\circ}+i\sin135^{\circ})$ It is known that $\cos135^{\circ}=-\frac{\sqrt 2}{2}$ and $\sin135^{\circ}=\frac{\sqrt 2}{2}$ Substituting these values in the expression and solving: $6(\cos135^{\circ}+i\sin135^{\circ})=6(-\frac{\sqrt 2}{2}+\frac{\sqrt 2}{2}i)=-3\sqrt 2+3i\sqrt 2$
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