Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 7 - Quiz (Sections 7.1-7.3) - Page 326: 9


BC has a length of 25.24983 miles

Work Step by Step

We can use the law of cosines to find the length $AB$: $BC^2 = AB^2+AC^2-2(AB)(AC)~cos~A$ $BC = \sqrt{AB^2+AC^2-2(AB)(AC)~cos~A}$ $BC = \sqrt{(22.47928~mi)^2+(28.14276~mi)^2-(2)(22.47928~mi)(28.14276~mi)~cos~58.56989^{\circ}}$ $BC = \sqrt{637.5539346388~mi^2}$ $BC = 25.24983~mi$ BC has a length of 25.24983 miles
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