## Trigonometry (11th Edition) Clone

The speed of the wind $u$ is 11.3 mph. The wind is blowing toward the northwest direction at a bearing of $315^{\circ}$.
$u = -8~i+8~j$ The speed of the wind is the magnitude of the vector $u$. We can find the magnitude of the vector $u$: $\vert u \vert = \sqrt{(-8)^2+8^2}$ $\vert u \vert = 11.3$ The wind is blowing toward the northwest. Since the horizontal component is equal in magnitude to the vertical component, the wind is blowing at a bearing of $270^{\circ}+45^{\circ} = 315^{\circ}$. The speed of the wind $u$ is 11.3 mph. The wind is blowing toward the northwest direction at a bearing of $315^{\circ}$.