#### Answer

If $\frac{a~sin~B}{b}\gt 1$, then there is no triangle satisfying the given values, because there is no angle $A$ such that $sin~A \gt 1$

#### Work Step by Step

Given $a, b,$ and $B$, we can use the law of sines to find the angle $A$:
$\frac{b}{sin~B} = \frac{a}{sin~A}$
$sin~A = \frac{a~sin~B}{b}$
If $\frac{a~sin~B}{b}\gt 1$, then there is no triangle satisfying the given values, because there is no angle $A$ such that $sin~A \gt 1$