Answer
Sufficient information
Work Step by Step
$\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{ \sin C}$
Suppose that $\angle A$ and $\angle B$ are known.
Then
$m\angle C=180-(m\angle A+m\angle B)$
Since $c$ being included side of angle A and angle B is already known, then
$ \frac{c}{ \sin\angle C}$ is a known quantity.
Let $ \frac{c}{ \sin\angle C}= k$
Now using the Law of Sine:
$\frac{a}{\sin\angle A}=\frac{c}{\sin\angle C}$
$a=\frac{c}{\sin\angle C} \times \sin\angle A=k\sin\angle A$
Similarly $b$ may be calculated as
$b=k \sin\angle B$
So there is sufficient information to solve the triangle.
