Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Test - Page 294: 19a


$x = \frac{4}{5}$

Work Step by Step

Let $\theta = arctan~\frac{4}{3}$ Then $tan~\theta = \frac{4}{3} = \frac{opp}{adj}$ If the opposite side is 4 and the adjacent side is 3, then the hypotenuse is $\sqrt{4^2+3^2} = 5$ Then $sin~\theta = \frac{4}{5}$ Therefore, $arcsin~\frac{4}{5} = \theta = arctan ~\frac{4}{3}$ $x = \frac{4}{5}$
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