Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Quiz (Sections 6.1-6.3) - Page 282: 2b



Work Step by Step

$$y=\tan^{-1}\sqrt3$$ *Remember: $\tan^{-1}A=x$ means that $\tan x=A$ Therefore, to find $y$, we need to recall which value of $y$ would have $\tan y=\sqrt3$. $\tan y\gt0$ shows that we can find a value of $y$ in either quadrant I or III of the unit circle. The choice is arbitrary. I would choose quadrant I here. In quadrant I, $\frac{\pi}{3}$ is the value of the angle with which $\tan(\frac{\pi}{3})=\sqrt3$ Therefore, $$y=\frac{\pi}{3}$$
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