Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Inverse Circular Functions and Trigonometric Equations - Section 6.4 Equations Involving Inverse Trigonometric Functions - 6.4 Exercises - Page 287: 51a

Answer

$tan~\alpha = \frac{x}{z}$ $tan~\beta = \frac{x+y}{z}$

Work Step by Step

From the diagram: $tan~\alpha = \frac{x}{z}$ $tan~\beta = \frac{x+y}{z}$
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