Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Inverse Circular Functions and Trigonometric Equations - Section 6.3 Trigonometric Equations II - 6.3 Exercises - Page 279: 29


There are no solutions.

Work Step by Step

$8~sec^2~\frac{x}{2} = 4$ $sec^2~\frac{x}{2} = \frac{1}{2}$ $sec~\frac{x}{2} = \pm~\sqrt{\frac{1}{2}}$ However, there is no angle $\frac{x}{2}$ such that $\vert sec ~\frac{x}{2}\vert \lt 1$. Therefore, there are no solutions.
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