## Trigonometry (11th Edition) Clone

$8~sec^2~\frac{x}{2} = 4$ $sec^2~\frac{x}{2} = \frac{1}{2}$ $sec~\frac{x}{2} = \pm~\sqrt{\frac{1}{2}}$ However, there is no angle $\frac{x}{2}$ such that $\vert sec ~\frac{x}{2}\vert \lt 1$. Therefore, there are no solutions.