Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Inverse Circular Functions and Trigonometric Equations - Section 6.1 Inverse Circular Functions - 6.1 Exercises - Page 263: 7d

Answer

-2 is not part of the domain

Work Step by Step

arc$\sin (-2)=\sin^{-1} (-2)$ Comparing the above expression to $y=\sin^{-1} x$, this means that we need to find $y$ when $x=-2$. Since $-2$ is not part of the domain, this means that arc$\sin (-2)$ is not defined.
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