## Trigonometry (11th Edition) Clone

$AB$ is a radius of the circle and $BD$ is a radius of the circle. Therefore, $AB = BD$. Since the two sides $AB$ and $BD$ are equal, the triangle $ABD$ is an isosceles triangle.
$AB$ is a radius of the circle and $BD$ is a radius of the circle. Therefore, $AB = BD$. In the triangle $ABD$, since the two sides $AB$ and $BD$ are equal, the triangle $ABD$ is an isosceles triangle.