Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 5 - Trigonometric Identities - Section 5.6 Half-Angle Identities - 5.6 Exercises - Page 244: 77

Answer

$AB$ is a radius of the circle and $BD$ is a radius of the circle. Therefore, $AB = BD$. Since the two sides $AB$ and $BD$ are equal, the triangle $ABD$ is an isosceles triangle.

Work Step by Step

$AB$ is a radius of the circle and $BD$ is a radius of the circle. Therefore, $AB = BD$. In the triangle $ABD$, since the two sides $AB$ and $BD$ are equal, the triangle $ABD$ is an isosceles triangle.
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